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(D) $P_4O_{10}$ is a powerful dehydrating agent. When concentrated $H_2SO_4$ is heated with $P_4O_{10}$,it undergoes dehydration to form sulfur trioxi

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$SO_3$

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(D) $P_4O_{10}$ is a powerful dehydrating agent. When concentrated $H_2SO_4$ is heated with $P_4O_{10}$,it undergoes dehydration to form sulfur trioxide $(SO_3)$. The reaction is: $H_2SO_4 + P_4O_{10} \rightarrow SO_3 + H_3PO_4$ (or simply $H_2SO_4 \xrightarrow{P_4O_{10}} SO_3 + H_2O$). $SO_3$ is also known as the anhydride of $H_2SO_4$.

What is produced by the dehydration of concentrated $H_2SO_4$ in the presence of $P_4O_{10}$?

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