Which of the following bonds is the most pola | vedclass

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Question

(C) The polarity of a bond depends on the electronegativity difference between the bonded atoms. The electronegativity values are: $N = 3.04$,$F = 3.9

Vedclass · Accepted Answer

$N - F$

Vedclass · Answer

(C) The polarity of a bond depends on the electronegativity difference between the bonded atoms. The electronegativity values are: $N = 3.04$,$F = 3.98$,$O = 3.44$,$Cl = 3.16$. Calculating the differences: $|N - Cl| = |3.04 - 3.16| = 0.12$ $|O - F| = |3.44 - 3.98| = 0.54$ $|N - F| = |3.04 - 3.98| = 0.94$ $|N - N| = |3.04 - 3.04| = 0$ Since $N - F$ has the largest electronegativity difference,it is the most polar bond.

Which of the following bonds is the most polar?

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