$HI$ cannot be prepared by the reaction of concentrated $H_2SO_4$ with $KI$ because:
- A$HI$ is a stronger acid than $H_2SO_4$.
- B$HI$ is more volatile than $H_2SO_4$.
- C$H_2SO_4$ is an oxidizing agent.
- D$H_2SO_4$ forms a complex.
Explore More
Similar Questions
Find out which of the following statements are true or false:
$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ is $(n-1)$.
$(b)$ When $F_2$ reacts with $H_2O$,it forms $HF$,$O_2$,and $O_3$.
$(c)$ $XeF_6$ on hydrolysis shows a disproportionation reaction.
$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al(OH)_3$ as a final product.
$(a)$ Number of $S-S$ bonds in $H_2S_nO_6$ is $(n-1)$.
$(b)$ When $F_2$ reacts with $H_2O$,it forms $HF$,$O_2$,and $O_3$.
$(c)$ $XeF_6$ on hydrolysis shows a disproportionation reaction.
$(d)$ $Al$ metal on reacting with dilute $NaOH$ gives a white precipitate of $Al(OH)_3$ as a final product.
$A$ gas reacts with $CaO$,but not with $NaHCO_3$. The gas is
Easy
View SolutionThe strongest reducing agent among the given halide ions is:
Easy
View SolutionWhich of the following statements is correct regarding the molecules $ClO_3$ and $Cl_2O_6$?
Medium
View SolutionWhat is the color of the solution when iodine is dissolved in $CCl_4$?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo