What is the hybridization and structure of $XeF_4$?
- A$sp^3d$,Trigonal bipyramidal
- B$sp^3$,Tetrahedral
- C$sp^3d^2$,Square planar
- D$sp^3d^2$,Octahedral
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Similar Questions
Match the following List-$I$ (Hybridisation) with List-$II$ (Shape):
List-$I$ (Hybridisation) List-$II$ (Shape) $A$. $dsp^2$ $I$. Square planar $B$. $sp^3$ $II$. Tetrahedral $C$. $d^2sp^3$ $III$. Octahedral $D$. $sp^3d$ $IV$. Trigonal bipyramidal
| List-$I$ (Hybridisation) | List-$II$ (Shape) |
|---|---|
| $A$. $dsp^2$ | $I$. Square planar |
| $B$. $sp^3$ | $II$. Tetrahedral |
| $C$. $d^2sp^3$ | $III$. Octahedral |
| $D$. $sp^3d$ | $IV$. Trigonal bipyramidal |
Which one of the following is a planar molecule?
Medium
View SolutionMethane is tetrahedral but not square planar in nature,prove it.
Medium
View SolutionFind the hybridisation of the $C_1$,$C_2$,and $C_3$ labelled carbon atoms in the given molecule: $H-C \equiv C_1-C_2H-C_3H=CH_2$
In $sp$ hybridisation,the shape is:
Medium
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