The atomic mass of noble gases is determined by which of the following relationships?
- A$Atomic \ mass = Equivalent \ mass \times Valency$
- B$Atomic \ mass = Equivalent \ mass / Valency$
- C$Atomic \ mass = 2 \times Vapor \ density = Molecular \ mass$
- D$Atomic \ mass = Valency / Equivalent \ mass$
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Similar Questions
$1.5 \ g$ of $CdCl_2$ was found to contain $0.9 \ g$ of $Cd$. Calculate the atomic weight of $Cd$.
DifficultAP EAMCET 2009
View SolutionMatch column $-I$ and column $-II$ with the correct molar mass values:
Column $-I$ Column $-II$ $(i)$ Barium sulphate $(a)$ $1877 \ g/mol$ $(ii)$ Magnesium pyrophosphate $(b)$ $235 \ g/mol$ $(iii)$ Ammonium phosphomolybdate $(c)$ $188 \ g/mol$ $(iv)$ Silver chloride $(d)$ $222 \ g/mol$ $(v)$ Silver bromide $(e)$ $143.5 \ g/mol$ $(vi)$ Silver iodide $(f)$ $233 \ g/mol$
| Column $-I$ | Column $-II$ |
| $(i)$ Barium sulphate | $(a)$ $1877 \ g/mol$ |
| $(ii)$ Magnesium pyrophosphate | $(b)$ $235 \ g/mol$ |
| $(iii)$ Ammonium phosphomolybdate | $(c)$ $188 \ g/mol$ |
| $(iv)$ Silver chloride | $(d)$ $222 \ g/mol$ |
| $(v)$ Silver bromide | $(e)$ $143.5 \ g/mol$ |
| $(vi)$ Silver iodide | $(f)$ $233 \ g/mol$ |
Medium
View SolutionIf the equivalent weight of a metal $(M)$ is $x$ and the formula of its oxide is $M_mO_n$,then the atomic weight of $M$ is ......
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View SolutionWhat will be the mass of one atom of $^{12}C$ in grams?
Easy
View SolutionThe equivalent mass of iodine in the following reaction is $I_2 + 2S_2O_3^{2-} \longrightarrow 2I^{-} + S_4O_6^{2-}$
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