In the case of alkali metal halides,the covalent character decreases in the order:
- A$MF > MCl > MBr > MI$
- B$MF > MCl > MI > MBr$
- C$MI > MBr > MCl > MF$
- D$MCl > MI > MBr > MF$
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Similar Questions
Arrange the following in increasing order of their covalent character.
$CaF_{2}$,$CaCl_{2}$,$CaBr_{2}$,$CaI_{2}$
Choose the correct answer from the options given below.
$CaF_{2}$,$CaCl_{2}$,$CaBr_{2}$,$CaI_{2}$
Choose the correct answer from the options given below.
State $Fajans$ rules for the partial covalent character of ionic bonds.
Medium
View SolutionMagnesium cation $(Mg^{2+})$ has a polarising power close to that of:
Which one of the following is the highest melting halide?
Easy
View Solution$STATEMENT-1$: Boron always forms covalent bonds.
Because
$STATEMENT-2$: The small size of $B^{3+}$ favors the formation of covalent bonds.
Because
$STATEMENT-2$: The small size of $B^{3+}$ favors the formation of covalent bonds.
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