Identify the product B in the following react | vedclass

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(A) $1$. The starting material is $1,4-	ext{cyclohexadiene-1,4-dicarboxylic acid}$.$2$. Treatment with $NaOH$ converts the carboxylic acid groups int

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$1,4-$cyclohexadiene

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(A) $1$. The starting material is $1,4-	ext{cyclohexadiene-1,4-dicarboxylic acid}$.$2$. Treatment with $NaOH$ converts the carboxylic acid groups into carboxylate ions,forming the disodium salt $A$ $(1,4-	ext{cyclohexadiene-1,4-dicarboxylate})$.$3$. Kolbe electrolysis of the salt of a dicarboxylic acid involves the decarboxylation and the formation of a new carbon-carbon bond between the radical intermediates generated at the anode.$4$. In this specific case,the decarboxylation of the $1,4-	ext{cyclohexadiene-1,4-dicarboxylate}$ dianion leads to the formation of $1,4-	ext{cyclohexadiene}$ as the product $B$ after the loss of $CO_2$ and subsequent radical coupling/disproportionation steps.

Identify the product $B$ in the following reaction sequence:
$1,4-\text{cyclohexadiene-1,4-dicarboxylic acid}$ $\xrightarrow{NaOH} A$ $\xrightarrow{\text{Kolbe electrolysis}} B$

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Identify the product $B$ in the following reaction sequence:$1,4-\text{cyclohexadiene-1,4-dicarboxylic acid}$ $\xrightarrow{NaOH} A$ $\xrightarrow{\text{Kolbe electrolysis}} B$