4-Methylaniline on heating with alcoholic KOH | vedclass

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Question

(A) The reaction of a primary amine (aromatic or aliphatic) with chloroform $(CHCl_3)$ and alcoholic potassium hydroxide $(KOH)$ is known as the carby

Vedclass · Accepted Answer

$4-$Methylphenyl isocyanide

Vedclass · Answer

(A) The reaction of a primary amine (aromatic or aliphatic) with chloroform $(CHCl_3)$ and alcoholic potassium hydroxide $(KOH)$ is known as the carbylamine reaction or isocyanide test.In this reaction,the amine group $(-NH_2)$ is converted into an isocyanide group $(-NC)$.For $4$-methylaniline ($p$-toluidine),the reaction is:$CH_3-C_6H_4-NH_2 + CHCl_3 + 3KOH \rightarrow CH_3-C_6H_4-NC + 3KCl + 3H_2O$The product formed is $4$-methylphenyl isocyanide.

$4$-Methylaniline on heating with alcoholic $KOH$ in the presence of chloroform gives :-

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