CH_3OH and C_2H_5OH may be distinguished chem | vedclass

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(B) The Iodoform test is used to distinguish compounds containing a $CH_3CH(OH)-$ group or a $CH_3CO-$ group.Ethanol $(C_2H_5OH)$ contains a methyl gr

Vedclass · Accepted Answer

By the action of $I_2 + Na_2CO_3$

Vedclass · Answer

(B) The Iodoform test is used to distinguish compounds containing a $CH_3CH(OH)-$ group or a $CH_3CO-$ group.Ethanol $(C_2H_5OH)$ contains a methyl group attached to the carbon bearing the hydroxyl group $(CH_3CH_2OH)$,which gives a positive Iodoform test.Methanol $(CH_3OH)$ does not contain this structural unit and does not give the Iodoform test.$CH_3OH + I_2 + Na_2CO_3 \xrightarrow{\Delta} 	ext{No reaction}$$C_2H_5OH + 4I_2 + 6Na_2CO_3 \xrightarrow{\Delta} CHI_3 (	ext{yellow ppt}) + HCOONa + 5NaI + 5NaHCO_3 + 2H_2O$Therefore,$I_2 + Na_2CO_3$ is the correct reagent.

$CH_3OH$ and $C_2H_5OH$ may be distinguished chemically by:

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