IUPAC name of the following compound isCH_3-C | vedclass

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(C) $1$. Identify the longest carbon chain containing both the double bond and the triple bond. The chain has $6$ carbon atoms,so the parent alkane is

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Hex$-4-$en$-1-$yne

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(C) $1$. Identify the longest carbon chain containing both the double bond and the triple bond. The chain has $6$ carbon atoms,so the parent alkane is hexane.$2$. Number the chain from the end that gives the lower locant to the multiple bonds. Numbering from the left gives the double bond at $C-2$ and the triple bond at $C-5$. Numbering from the right gives the triple bond at $C-1$ and the double bond at $C-4$.$3$. According to $IUPAC$ rules,if both double and triple bonds are present,the double bond is given priority for the lower number if there is a choice. However,the rule states we choose the set of locants that is lower. Comparing $(2, 5)$ and $(1, 4)$,the set $(1, 4)$ is lower.$4$. Therefore,the correct numbering starts from the right: $C-1$ is the triple bond,$C-4$ is the double bond.$5$. The name is constructed as $Hex-4-en-1-yne$.

$IUPAC$ name of the following compound is
$CH_3-CH=CH-CH_2-C\equiv CH$

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$IUPAC$ name of the following compound is$CH_3-CH=CH-CH_2-C\equiv CH$