100 coplanar forces,each equal to 10 , N,act | vedclass

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(D) The total angle covered by $100$ forces is given by $	heta_{total} = 100 	imes \frac{\pi}{50} = 2\pi$. Since the forces are coplanar and distrib

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(D) The total angle covered by $100$ forces is given by $	heta_{total} = 100 	imes \frac{\pi}{50} = 2\pi$. Since the forces are coplanar and distributed symmetrically such that they form a closed polygon of vectors,the resultant force is zero. Alternatively,for $n$ forces of equal magnitude $F$ acting at equal angles $\Delta	heta$ between consecutive forces,the resultant is zero if $n \Delta	heta = 2\pi$. Here,$n = 100$ and $\Delta	heta = \pi/50$,so $n \Delta	heta = 100 	imes (\pi/50) = 2\pi$. Therefore,the resultant force is $0 \, N$.

$100$ coplanar forces,each equal to $10 \, N$,act on a body. Each force makes an angle of $\pi / 50$ with the preceding force. What is the resultant of the forces? $(N)$

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