H_{2(g)} + I_{2(g)} rightleftharpoons 2HI_{(g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the reaction $H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$,the change in the number of moles of gaseous products and reactants is $\Delta

Vedclass · Accepted Answer

Unaffected by change in pressure

Vedclass · Answer

(C) For the reaction $H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$,the change in the number of moles of gaseous products and reactants is $\Delta n_g = n_p - n_r = 2 - (1 + 1) = 0$.Since $\Delta n_g = 0$,the equilibrium position is unaffected by a change in pressure.Given $\Delta H = +q \ cal$,the reaction is endothermic.According to Le Chatelier's principle,increasing the temperature favours the forward (endothermic) reaction,while decreasing the temperature favours the backward reaction.Therefore,the formation of $HI$ is unaffected by a change in pressure.

$H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$,$\Delta H = +q \ cal$. The formation of $HI$ is:

Similar Questions

Consider the reaction $HCN_{(aq)} \Leftrightarrow H_{(aq)}^{+} + CN_{(aq)}^{-}$. At equilibrium,the addition of $CN_{(aq)}^{-}$ would

$A$ vapor at atmospheric pressure is gradually heated from $25\,^oC$. Initially,its color deepens,but above $160\,^oC$,the color fades. At $600\,^oC$,the vapor becomes almost colorless. However,increasing the pressure at this temperature makes the color deep again. What is this vapor?

Consider the heterogeneous equilibrium in a closed container:
$NH_4HS_{(s)} \rightleftharpoons NH_{3(g)} + H_2S_{(g)}$
If more $NH_4HS_{(s)}$ is added to the equilibrium,what will be the effect on the system?

For an exothermic reaction,the equilibrium constant:

In which of the following reactions will a change in pressure not affect the rate of reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module