A 240 mL mixture of CO_2 and CO is passed ov | vedclass

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(C) Let the initial volume of $CO$ be $x \ mL$. Therefore,the initial volume of $CO_2$ is $(240 - x) \ mL$. The chemical reaction is: $CO_{2(g)} + C_{

Vedclass · Accepted Answer

$180$

Vedclass · Answer

(C) Let the initial volume of $CO$ be $x \ mL$. Therefore,the initial volume of $CO_2$ is $(240 - x) \ mL$. The chemical reaction is: $CO_{2(g)} + C_{(s)} \longrightarrow 2CO_{(g)}$. According to the reaction,$1 \ volume$ of $CO_2$ produces $2 \ volumes$ of $CO$. So,$(240 - x) \ mL$ of $CO_2$ produces $2(240 - x) \ mL$ of $CO$. The final volume of the mixture is the sum of the initial $CO$ and the $CO$ produced from $CO_2$: $x + 2(240 - x) = 300$. Solving for $x$: $x + 480 - 2x = 300$. $-x = 300 - 480$. $-x = -180$. $x = 180 \ mL$.

$A$ $240 \ mL$ mixture of $CO_2$ and $CO$ is passed over red-hot coke. The $CO_2$ is completely reduced to $CO$. When the resulting gas is brought to the same temperature and pressure,the volume becomes $300 \ mL$. What is the volume of $CO$ in the original mixture in $mL$?

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