A vessel contains equal masses of hydrogen,he | vedclass

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(D) Let the mass of each gas be $m \ g$.Number of moles of $H_2$ $(n_{H_2})$ = $\frac{m}{2}$.Number of moles of $He$ $(n_{He})$ = $\frac{m}{4}$.Number

Vedclass · Accepted Answer

$800$

Vedclass · Answer

(D) Let the mass of each gas be $m \ g$.Number of moles of $H_2$ $(n_{H_2})$ = $\frac{m}{2}$.Number of moles of $He$ $(n_{He})$ = $\frac{m}{4}$.Number of moles of $CH_4$ $(n_{CH_4})$ = $\frac{m}{16}$.Total moles $(n_{total})$ = $\frac{m}{2} + \frac{m}{4} + \frac{m}{16} = \frac{8m + 4m + m}{16} = \frac{13m}{16}$.Mole fraction of $H_2$ $(x_{H_2})$ = $\frac{n_{H_2}}{n_{total}} = \frac{m/2}{13m/16} = \frac{1}{2} 	imes \frac{16}{13} = \frac{8}{13}$.Partial pressure of $H_2$ $(P_{H_2})$ = $x_{H_2} 	imes P_{total} = \frac{8}{13} 	imes 1300 \ torr = 800 \ torr$.

$A$ vessel contains equal masses of hydrogen,helium,and methane. The total pressure of the mixture is $1300 \ torr$. What is the partial pressure of hydrogen gas in $torr$?

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