The root mean square speed of O_2 at STP is . | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formula for root mean square speed $(u_{rms})$ is given by $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $STP$,$T = 273.15 \ K$ and $R = 8.314 \ J \cdot

Vedclass · Accepted Answer

$4.61 	imes 10^4$

Vedclass · Answer

(A) The formula for root mean square speed $(u_{rms})$ is given by $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $STP$,$T = 273.15 \ K$ and $R = 8.314 \ J \cdot K^{-1} \cdot mol^{-1}$.The molar mass of $O_2$ $(M)$ is $32 \ g/mol = 32 	imes 10^{-3} \ kg/mol$.Substituting the values: $u_{rms} = \sqrt{\frac{3 	imes 8.314 	imes 273.15}{32 	imes 10^{-3}}} \approx \sqrt{\frac{6813.5}{0.032}} \approx \sqrt{212922} \approx 461.4 \ m/s$.To convert $m/s$ to $cm/s$,multiply by $100$: $461.4 	imes 100 = 46140 \ cm/s = 4.614 	imes 10^4 \ cm/s$.

The root mean square speed of $O_2$ at $STP$ is ........ $cm/s$.

Similar Questions

Explain the Maxwell-Boltzmann distribution law with a graph.

At what temperature $T$ will the average speed of $CO_2$ gas be $9.0 \times 10^4 \ cm \ s^{-1}$ (in $K$)?

If the most probable speed of methane $(CH_4)$ at a certain temperature is $400 \ ms^{-1}$,what is the kinetic energy of one mole of methane at the same temperature in $J$?

The $RMS$ velocity of $CO$ gas molecules at $27^{\circ} C$ is approximately $1000 \ m / s$. For molecules at $600 \ K$, the $RMS$ velocity is approximately (in $m / s$)

Explain the following terms:
$(i) u_{mp}$
$(ii) u_{av}$
$(iii) \overline{u}^2$
$(iv) u_{rms}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module