Which of the following has the maximum number | vedclass

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(D) The number of neutrons $(n)$ is calculated using the formula: $n = A - Z$,where $A$ is the mass number and $Z$ is the atomic number.For $A$: $n =

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$_{93}Np^{237}$

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(D) The number of neutrons $(n)$ is calculated using the formula: $n = A - Z$,where $A$ is the mass number and $Z$ is the atomic number.For $A$: $n = 232 - 90 = 142$.For $B$: $n = 231 - 91 = 140$.For $C$: $n = 235 - 92 = 143$.For $D$: $n = 237 - 93 = 144$.Comparing the values,$144 > 143 > 142 > 140$. Thus,$_{93}Np^{237}$ has the maximum number of neutrons.

Which of the following has the maximum number of neutrons?

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