The value of one Einstein for radiation of wa | vedclass

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(C) The energy of one Einstein is defined as the energy of one mole of photons.$E = \frac{N_A 	imes h 	imes c}{\lambda}$Given: $\lambda = 9000 \ \ma

Vedclass · Accepted Answer

$1.329 	imes 10^{5}$

Vedclass · Answer

(C) The energy of one Einstein is defined as the energy of one mole of photons.$E = \frac{N_A 	imes h 	imes c}{\lambda}$Given: $\lambda = 9000 \ \mathring{A} = 9000 	imes 10^{-10} \ m = 9 	imes 10^{-7} \ m$,$N_A = 6.022 	imes 10^{23} \ mol^{-1}$,$h = 6.626 	imes 10^{-34} \ J \cdot s$,$c = 3 	imes 10^8 \ m/s$.$E = \frac{6.022 	imes 10^{23} 	imes 6.626 	imes 10^{-34} 	imes 3 	imes 10^8}{9 	imes 10^{-7}}$$E = \frac{11.97 	imes 10^{-3}}{9 	imes 10^{-7}} \approx 1.33 	imes 10^5 \ J \ mol^{-1}$.

The value of one Einstein for radiation of wavelength $9000 \ \mathring{A}$ is .............

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