In a H atom,if the angular momentum of an ele | vedclass

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(C) According to Bohr's postulate,angular momentum $L = \frac{nh}{2\pi}$.Given $L = 3.164 	imes 10^{-34} \ kg \ m^2 \ s^{-1}$ and $h = 6.626 	imes 1

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(C) According to Bohr's postulate,angular momentum $L = \frac{nh}{2\pi}$.Given $L = 3.164 	imes 10^{-34} \ kg \ m^2 \ s^{-1}$ and $h = 6.626 	imes 10^{-34} \ J \ s$.$n = \frac{L 	imes 2\pi}{h} = \frac{3.164 	imes 10^{-34} 	imes 2 	imes 3.1416}{6.626 	imes 10^{-34}} \approx 3$.The energy of an electron in the $n^{th}$ orbit is given by $E_n = -13.6 	imes \frac{Z^2}{n^2} \ eV$.For $H$ atom,$Z = 1$ and $n = 3$.$E_3 = -13.6 	imes \frac{1^2}{3^2} = -13.6 	imes \frac{1}{9} \approx -1.51 \ eV$.

In a $H$ atom,if the angular momentum of an electron is $3.164 \times 10^{-34} \ kg \ m^2 \ s^{-1}$,what is the energy of the electron in that orbit in $eV$?

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