(B) For the $3d^5$ configuration,the number of unpaired electrons $(n)$ is $5$.The formula for spin multiplicity is $2S + 1$,where $S = \sum s$.Since

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(B) For the $3d^5$ configuration,the number of unpaired electrons $(n)$ is $5$.The formula for spin multiplicity is $2S + 1$,where $S = \sum s$.Since each of the $5$ electrons has a spin of $+1/2$,the total spin $S = 5 \times (1/2) = 5/2$.Spin multiplicity $= 2(5/2) + 1 = 5 + 1 = 6$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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What is the spin multiplicity of an electron in the $3d^5$ electronic configuration?

A
$5$
B
$6$
C
$4$
D
$25$

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Quantum number, Electronic configuration and Shape of orbitals

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What is the spin multiplicity of an electron in the $3d^5$ electronic configuration?

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