The angular momentum of an electron in a 2s o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The angular momentum of an electron is given by the formula: $L = \sqrt{l(l+1)} \frac{h}{2\pi}$,where $l$ is the azimuthal quantum number.For an $

Vedclass · Accepted Answer

$4s$

Vedclass · Answer

(C) The angular momentum of an electron is given by the formula: $L = \sqrt{l(l+1)} \frac{h}{2\pi}$,where $l$ is the azimuthal quantum number.For an $s$ orbital,the value of $l$ is $0$.Therefore,the angular momentum of an electron in a $2s$ orbital is $\sqrt{0(0+1)} \frac{h}{2\pi} = 0$.Among the given options,only $s$ orbitals have $l = 0$.Thus,the angular momentum of an electron in a $4s$ orbital is also $\sqrt{0(0+1)} \frac{h}{2\pi} = 0$.Hence,the angular momentum of a $2s$ electron is equal to that of a $4s$ electron.

The angular momentum of an electron in a $2s$ orbital is equal to the angular momentum of an electron in which of the following orbitals?

Similar Questions

In the ground state, an element has $13$ electrons in the $M$ shell. The element is

What is an atomic orbital?

Given:
$(A)\ n = 5, m_l = +1$
$(B)\ n = 2, l = 1, m_l = -1, m_s = -1/2$
The maximum number of electron$(s)$ in an atom that can have the quantum numbers as given in $(A)$ and $(B)$ are respectively:

Which of the following sequences is correct according to the Aufbau principle?

The number of radial (spherical) nodes in a $4p$ orbital is $....$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module