What is the maximum number of electrons that can be accommodated in a single $p$ orbital?

Describe the orbitals with the following quantum numbers using $s, p, d, f$ notations:
$(a) \ n = 2, l = 1$
$(b) \ n = 4, l = 0$
$(c) \ n = 5, l = 3$
$(d) \ n = 3, l = 2$

For an electron with $n = 3$,there is only one radial node. The orbital angular momentum of the electron will be

The maximum number of electrons in a $p$-orbital with $n = 5$ and $m = 1$ is

Explain,giving reasons,which of the following sets of quantum numbers are not possible.
$(a)$ $n=0, l=0, m_{l}=0, m_{s}=+\frac{1}{2}$
$(b)$ $n=1, l=0, m_{l}=0, m_{s}=-\frac{1}{2}$
$(c)$ $n=1, l=1, m_{l}=0, m_{s}=+\frac{1}{2}$
$(d)$ $n=2, l=1, m_{l}=0, m_{s}=-\frac{1}{2}$
$(e)$ $n=3, l=3, m_{l}=-3, m_{s}=+\frac{1}{2}$
$(f)$ $n=3, l=1, m_{l}=0, m_{s}=+\frac{1}{2}$

Which one is a wrong statement?