If the quantum number values for the valence | vedclass

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(D) The given quantum numbers $n = 4, l = 0, m = 0$ correspond to the $4s$ orbital. This indicates that the valence electron is in the $4s$ subshell.

Vedclass · Accepted Answer

$19$ or $20$

Vedclass · Answer

(D) The given quantum numbers $n = 4, l = 0, m = 0$ correspond to the $4s$ orbital. This indicates that the valence electron is in the $4s$ subshell. The electronic configuration of the atom must end in $4s^1$ or $4s^2$. If the configuration ends in $4s^1$,the element is Potassium $(K)$,which has an atomic number of $19$. If the configuration ends in $4s^2$,the element is Calcium $(Ca)$,which has an atomic number of $20$. Therefore,the atomic number can be $19$ or $20$.

If the quantum number values for the valence shell electron of an atom are $n = 4, l = 0, m = 0$,then the atomic number of the element could be .........

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Assertion :- In $H$-atom,the energy of $3d$-level is smaller than $4s$-level.
Reason :- In multi-electron species,an orbital with lower value of $(n+\ell)$ has energy smaller than the orbital with larger value of $(n+\ell)$.

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