How many exchange pairs are possible for a 3d | vedclass

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(C) The number of exchange pairs for a given electronic configuration is calculated using the formula: $N = \frac{n(n-1)}{2}$,where $n$ is the number

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$10$

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(C) The number of exchange pairs for a given electronic configuration is calculated using the formula: $N = \frac{n(n-1)}{2}$,where $n$ is the number of electrons with parallel spins.For a $3d^5$ configuration,all $5$ electrons have parallel spins according to Hund's rule.Substituting $n = 5$ into the formula:$N = \frac{5(5-1)}{2} = \frac{5 	imes 4}{2} = \frac{20}{2} = 10$.Thus,there are $10$ possible exchange pairs.

How many exchange pairs are possible for a $3d^5$ electronic configuration?

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