If the market prices of table salt (NaCl) and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The molar mass of $NaCl = 23 + 35.5 = 58.5 \, g/mol$.Given that $1000 \, g$ of $NaCl$ costs $Rs. 4$.Therefore,the cost of $1$ mole $(58.5 \, g)$ o

Vedclass · Accepted Answer

$0.234, 10.26$

Vedclass · Answer

(A) The molar mass of $NaCl = 23 + 35.5 = 58.5 \, g/mol$.Given that $1000 \, g$ of $NaCl$ costs $Rs. 4$.Therefore,the cost of $1$ mole $(58.5 \, g)$ of $NaCl = \frac{58.5 	imes 4}{1000} = 0.234 \, Rs$.The molar mass of table sugar $(C_{12}H_{22}O_{11}) = (12 	imes 12) + (22 	imes 1) + (11 	imes 16) = 144 + 22 + 176 = 342 \, g/mol$.Given that $1000 \, g$ of sugar costs $Rs. 30$.Therefore,the cost of $1$ mole $(342 \, g)$ of sugar $= \frac{342 	imes 30}{1000} = 10.26 \, Rs$.Thus,the prices are $0.234 \, Rs$ and $10.26 \, Rs$ respectively.

If the market prices of table salt $(NaCl)$ and table sugar $(C_{12}H_{22}O_{11})$ are $Rs. 4$ per $kg$ and $Rs. 30$ per $kg$ respectively,then the market price of $1$ mole of each will be,respectively,..... $Rs$.

Similar Questions

$6.02 \times 10^{20}$ molecules of urea are present in $100 \ mL$ of its solution. The concentration of urea solution is ......... $M$.

$A$ quantity of aluminium has a mass of $54.0 \ g$. What is the mass of the same number of magnesium atoms? ........... $g$

How many molecules are present in $22400 \ cm^3$ of a gas at $STP$?

What does $1 \text{ mole}$ of $CO_2$ contain?

$6.02 \times 10^{20}$ molecules of urea are present in $100 \ mL$ of its solution. The concentration of solution is $.... M$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module