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(A) To find the number of atoms,we calculate the number of moles of molecules and multiply by the number of atoms per molecule.$A)$ $1 \ g$ of $C_4H_{

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$1 \ g$ of butane $(C_4H_{10})$

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(A) To find the number of atoms,we calculate the number of moles of molecules and multiply by the number of atoms per molecule.$A)$ $1 \ g$ of $C_4H_{10}$: Molar mass = $58 \ g/mol$. Moles of molecules = $1/58$. Atoms per molecule = $14$. Total atoms $\propto 14/58 \approx 0.241$.$B)$ $1 \ g$ of $N_2$: Molar mass = $28 \ g/mol$. Moles of molecules = $1/28$. Atoms per molecule = $2$. Total atoms $\propto 2/28 \approx 0.071$.$C)$ $1 \ g$ of $Ag$: Molar mass = $108 \ g/mol$. Moles of atoms = $1/108 \approx 0.009$.$D)$ $1 \ g$ of $H_2O$: Molar mass = $18 \ g/mol$. Moles of molecules = $1/18$. Atoms per molecule = $3$. Total atoms $\propto 3/18 \approx 0.167$.Comparing the values,$1 \ g$ of butane has the highest number of atoms.

Which of the following contains the greatest number of atoms?

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