If the density of iron is $7.86 \, g \, cm^{-3}$ and its atomic mass is $55.85 \, u$,then find the volume occupied by $1 \, mol$ of iron atoms in $cm^{3}$.
- A$22.8$
- B$7.11$
- C$3.64 \times 10^{24}$
- D$5.26$
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