If $30 \, mL$ of $H_2$ and $20 \, mL$ of $O_2$ react to form water,what remains at the end?

$N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}$
$20 \ g \quad \quad \quad \quad 5 \ g$
Consider the above reaction. The limiting reagent of the reaction and the number of moles of $NH_{3}$ formed are,respectively:

The maximum number of moles of $CaSO_4$ produced by the reaction of $0.5 \ mol$ of $H_2SO_4$ with $0.2 \ mol$ of $Ca(OH)_2$ is ........

When $22.4 \ L$ of $H_{2(g)}$ is mixed with $5.6 \ L$ of $Cl_{2(g)}$,each at $S.T.P.$,the moles of $HCl_{(g)}$ formed after completion of the reaction is closest to $.... \ mol$.

$50.0 \ kg$ of $N_{2(g)}$ and $10.0 \ kg$ of $H_{2(g)}$ are mixed to produce $NH_{3(g)}$. Calculate the amount of $NH_{3(g)}$ formed. Identify the limiting reagent in the production of $NH_{3(g)}$ in this situation.

When $5 \ mol$ of reactant $A$ reacts with $8 \ mol$ of reactant $B$ in a closed rigid container according to the reaction:
$3A_{(g)} + 4B_{(g)} \to 2C_{(g)}$
$10^{2} \ kJ$ of heat was liberated. The $\Delta_rH$ of the given balanced reaction in $kJ/mol$ at $300 \ K$ is: $[R = 8 \ J/mol \cdot K]$