(C) The molar mass of $Na_2CO_3$ is $106 \, g/mol$. The molarity $(M_1)$ of the original solution is calculated as: $M_1 = \frac{1000 \times \text{mas

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The molar mass of $Na_2CO_3$ is $106 \, g/mol$. The molarity $(M_1)$ of the original solution is calculated as: $M_1 = \frac{1000 \times \text{mass}}{M_m \times V(mL)} = \frac{1000 \times 2.65}{106 \times 250} = \frac{2650}{26500} = 0.1 \, M$. Using the dilution formula $M_1 V_1 = M_2 V_2$: Given $M_1 = 0.1 \, M$,$V_1 = 10 \, mL$,and $V_2 = 0.1 \, L = 100 \, mL$. $M_2 = \frac{M_1 V_1}{V_2} = \frac{0.1 \times 10}{100} = 0.01 \, M$.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

Medium

$A$ $250 \, mL$ solution of $Na_2CO_3$ contains $2.65 \, g$ of $Na_2CO_3$. If $10 \, mL$ of this solution is taken and diluted with distilled water up to $0.1 \, L$,what will be the molarity of the resulting solution (in $, M$)?

A
$0.1$
B
$0.001$
C
$0.01$
D
$1$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Some Basic Concepts of Chemistry

Subtopic

Chemical stoichiometry

$4.4 \ g$ of an unknown gas occupies $2.24 \ L$ of volume at standard temperature and pressure. The gas may be

Medium

View Solution

What volume (in $mL$) of $HCl$ solution containing $73 \ g$ per litre is required to completely neutralise sodium hydroxide solution,obtained by allowing $0.46 \ g$ of metallic sodium to act upon water?

MediumAP EAMCET 2017

View Solution

What will be the amount of $MgCl_2$ (in $g$) when $17 \ g$ of $HCl$ is reacted with an excess of $MgO$ in the following reaction: $MgO + 2HCl \to MgCl_2 + H_2O$?

Difficult

View Solution

$10 \ g$ of a piece of marble $(CaCO_3)$ was put into excess of dilute $HCl$ acid. When the reaction was complete,$1120 \ mL$ of $CO_2$ was obtained at $STP$. The percentage of pure $CaCO_3$ in the marble is $............ \%$.

Difficult

View Solution

$A$ gaseous mixture contains $CH_4$ and $C_2H_6$ in equimolecular proportion. The weight of $2.24 \ L$ of this mixture at $S.T.P.$ is :- .............. $g$

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ $250 \, mL$ solution of $Na_2CO_3$ contains $2.65 \, g$ of $Na_2CO_3$. If $10 \, mL$ of this solution is taken and diluted with distilled water up to $0.1 \, L$,what will be the molarity of the resulting solution (in $, M$)?

Similar Questions

$4.4 \ g$ of an unknown gas occupies $2.24 \ L$ of volume at standard temperature and pressure. The gas may be

What volume (in $mL$) of $HCl$ solution containing $73 \ g$ per litre is required to completely neutralise sodium hydroxide solution,obtained by allowing $0.46 \ g$ of metallic sodium to act upon water?

What will be the amount of $MgCl_2$ (in $g$) when $17 \ g$ of $HCl$ is reacted with an excess of $MgO$ in the following reaction: $MgO + 2HCl \to MgCl_2 + H_2O$?

$10 \ g$ of a piece of marble $(CaCO_3)$ was put into excess of dilute $HCl$ acid. When the reaction was complete,$1120 \ mL$ of $CO_2$ was obtained at $STP$. The percentage of pure $CaCO_3$ in the marble is $............ \%$.

$A$ gaseous mixture contains $CH_4$ and $C_2H_6$ in equimolecular proportion. The weight of $2.24 \ L$ of this mixture at $S.T.P.$ is :- .............. $g$

Vedclass Test Series

Exam Paper Generator

Online Exam Module