Which of the following is the correct order o | vedclass

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(A) The lattice energy of an ionic compound is directly proportional to the product of the charges of the ions $(q_1 	imes q_2)$ and inversely propor

Vedclass · Accepted Answer

$Al_2O_3 > CaO > MgBr_2 > NaCl$

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(A) The lattice energy of an ionic compound is directly proportional to the product of the charges of the ions $(q_1 	imes q_2)$ and inversely proportional to the inter-ionic distance $(r_0)$.Formula: $U \propto \frac{|q_1 q_2|}{r_0}$.Let us analyze the charges of the ions:$Al_2O_3$: $Al^{3+}$ and $O^{2-}$ (Product of charges = $3 	imes 2 = 6$)$CaO$: $Ca^{2+}$ and $O^{2-}$ (Product of charges = $2 	imes 2 = 4$)$MgBr_2$: $Mg^{2+}$ and $Br^-$ (Product of charges = $2 	imes 1 = 2$)$NaCl$: $Na^+$ and $Cl^-$ (Product of charges = $1 	imes 1 = 1$)Based on the product of charges,the order is $Al_2O_3 > CaO > MgBr_2 > NaCl$.

Which of the following is the correct order of lattice energy for the given ionic compounds?

Similar Questions

The ionic bonds $X^{+}Y^{-}$ are formed when
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$II$. ionization energy of $X$ is low
$III$. lattice energy of $XY$ is high
$IV$. lattice energy of $XY$ is low
Choose the correct code.

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The lattice energies of $NaCl$,$NaF$,$KCl$,and $RbCl$ follow the order:

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