Which of the following molecules is linear?

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(A) To determine the shape of the molecules,we look at their hybridization and $VSEPR$ theory: $1$. $BeCl_2$: Beryllium has $2$ valence electrons. It

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$BeCl_2$

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(A) To determine the shape of the molecules,we look at their hybridization and $VSEPR$ theory: $1$. $BeCl_2$: Beryllium has $2$ valence electrons. It forms two bonds with Chlorine atoms. The hybridization is $sp$,resulting in a linear geometry with a bond angle of $180^{\circ}$. $2$. $H_2O$: Oxygen has $6$ valence electrons. It forms two bonds with Hydrogen and has two lone pairs. The hybridization is $sp^3$,resulting in a bent or $V$-shape. $3$. $SO_2$: Sulfur has $6$ valence electrons. It forms two double bonds with Oxygen and has one lone pair. The hybridization is $sp^2$,resulting in a bent shape. $4$. $CH_4$: Carbon has $4$ valence electrons. It forms four bonds with Hydrogen. The hybridization is $sp^3$,resulting in a tetrahedral geometry. Therefore,$BeCl_2$ is the linear molecule.

List-$I$ (Molecule)	List-$II$ (Shape)
$A. SF_4$	$I. T\text{-shaped}$
$B. ClF_3$	$II. \text{Square planar}$
$C. BrF_5$	$III. \text{See-saw}$
$D. XeF_4$	$IV. \text{Square pyramidal}$

Similar Questions

The minimum $\angle FSF$ bond angle is present in:

Match the molecules in List-$I$ with their respective shapes in List-$II$.
List-$I$ (Molecule) List-$II$ (Shape)
$A. SF_4$ $I. T\text{-shaped}$
$B. ClF_3$ $II. \text{Square planar}$
$C. BrF_5$ $III. \text{See-saw}$
$D. XeF_4$ $IV. \text{Square pyramidal}$

Identify the molecule which contains a lone pair of electrons on the sulphur atom.

Which set of the following molecules has only one lone pair of electrons on their respective central atoms?
$(i)$ $SO_2$
$(ii)$ $XeF_4$
$(iii)$ $PbCl_2$
$(iv)$ $SF_4$
$(v)$ $ClF_3$

Identify the wrongly matched pair.
Molecule $\quad$ $\quad$ Shape or geometry of molecule

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