How is the F_2 molecule formed? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic number of fluorine $(F)$ is $9$. Its electronic configuration is $1s^2 2s^2 2p_x^2 2p_y^2 2p_z^1$. In the formation of the $F_2$ molecu

Vedclass · Accepted Answer

By axial overlap of $p-p$ orbitals

Vedclass · Answer

(A) The atomic number of fluorine $(F)$ is $9$. Its electronic configuration is $1s^2 2s^2 2p_x^2 2p_y^2 2p_z^1$. In the formation of the $F_2$ molecule,the half-filled $2p_z$ orbital of one fluorine atom overlaps axially with the half-filled $2p_z$ orbital of another fluorine atom. This axial overlap results in the formation of a sigma $(\sigma)$ bond. Therefore,the $F_2$ molecule is formed by the axial overlap of $p-p$ orbitals.

How is the $F_2$ molecule formed?

Similar Questions

The strongest bond is formed when atomic orbitals undergo:

In $N_2$ molecule,the atoms are bonded by

The correct order of the extent of overlapping is:

The total number of $\sigma$ and $\pi$-bonds present in the following compound is:

The number of $\sigma$ and $\pi$ bonds present in an ethylene molecule is respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module