An element _ZM^{19} has 10 neutrons in its nu | vedclass

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(C) The mass number $A$ is given as $19$ and the number of neutrons $n$ is $10$.We know that $A = Z + n$,where $Z$ is the atomic number (number of pro

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$p-$ block

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(C) The mass number $A$ is given as $19$ and the number of neutrons $n$ is $10$.We know that $A = Z + n$,where $Z$ is the atomic number (number of protons).Therefore,$Z = A - n = 19 - 10 = 9$.The atomic number $Z = 9$ corresponds to the element Fluorine $(F)$.The electronic configuration of Fluorine $(Z=9)$ is $1s^2 2s^2 2p^5$.Since the last electron enters the $p-$ orbital,the element belongs to the $p-$ block.

An element $_ZM^{19}$ has $10$ neutrons in its nucleus. To which block does it belong?

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