CH_3-CH(CH_3)-CH=CH_2 xrightarrow{DBr} text{P | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction follows an electrophilic addition mechanism involving a carbocation intermediate.First,the electrophile $D^+$ adds to the terminal ca

Vedclass · Accepted Answer

$CH_3-C(Br)(CH_3)-CH_2-CH_2D$

Vedclass · Answer

(C) The reaction follows an electrophilic addition mechanism involving a carbocation intermediate.First,the electrophile $D^+$ adds to the terminal carbon of the double bond in $CH_3-CH(CH_3)-CH=CH_2$ to form a secondary carbocation: $CH_3-CH(CH_3)-C^+H-CH_2D$.Next,a $1,2$-hydride shift occurs to convert the secondary carbocation into a more stable tertiary carbocation: $CH_3-C^+(CH_3)-CH_2-CH_2D$.Finally,the nucleophile $Br^-$ attacks the tertiary carbocation to form the major product: $CH_3-C(Br)(CH_3)-CH_2-CH_2D$.

$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{DBr} \text{Product (Major)}$. The product will be:

Similar Questions

The alkene $C_6H_{10}$ producing $OHC-(CH_2)_4-CHO$ on ozonolysis is

Assertion : $trans-2-Butene$ on reaction with $Br_2$ gives $meso-2,3-dibromobutane$.
Reason : The reaction involves $syn-addition$ of bromine.

The product obtained by the reaction of propene with $HBr$ in the presence of peroxide is......

Hardening of oil is done by

The reaction of ethylene with bromine in a methanol solution yields $1, 2-$dibromoethane as well as $BrCH_2CH_2OCH_3$. This is because ......

Vedclass Test Series

Exam Paper Generator

Online Exam Module