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(C) The given reaction sequence is the Gabriel phthalimide synthesis followed by the carbylamine reaction.Step $1$: Phthalimide reacts with $KOH$ to f

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Cyclohexyl isocyanide

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(C) The given reaction sequence is the Gabriel phthalimide synthesis followed by the carbylamine reaction.Step $1$: Phthalimide reacts with $KOH$ to form potassium phthalimide,which then reacts with cyclohexyl chloride via $S_N2$ mechanism to form $N$-cyclohexylphthalimide. Subsequent hydrolysis with $H_2O/\Delta$ yields cyclohexylamine $(X = C_6H_{11}NH_2)$.Step $2$: Cyclohexylamine $(X)$ reacts with $CHCl_3$ and $KOH$ (carbylamine reaction) to form cyclohexyl isocyanide $(Y = C_6H_{11}NC)$.Therefore,$Y$ is cyclohexyl isocyanide.

Identify the product $Y$ in the following reaction sequence:
Phthalimide $\xrightarrow[(2) \text{Cyclohexyl chloride}, (3) H_2O/\Delta]{(1) KOH} X$ $\xrightarrow{CHCl_3, KOH, \Delta} Y$

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Identify the product $Y$ in the following reaction sequence:Phthalimide $\xrightarrow[(2) \text{Cyclohexyl chloride}, (3) H_2O/\Delta]{(1) KOH} X$ $\xrightarrow{CHCl_3, KOH, \Delta} Y$