$A_2 + 2 \, B \to 2 \, AB$
$[A_2]$ $[B]$ $-d[A_2]/dt$
$0.1$ $0.2$ $1 \times 10^{-2} \, M \, s^{-1}$
$0.2$ $0.2$ $2 \times 10^{-2} \, M \, s^{-1}$
$0.2$ $0.4$ $8 \times 10^{-2} \, M \, s^{-1}$

The order of reaction with respect to $A_2$ and $B$ are respectively:

  • A
    $1, 2$
  • B
    $2, 1$
  • C
    $1, 1$
  • D
    $2, 2$

Explore More

Similar Questions

For a reaction $A + B \rightarrow \text{product}$,if $[A]$ is doubled keeping $[B]$ constant,the rate of reaction doubles. Calculate the order of reaction with respect to $A$.

Select the rate law that corresponds to the data shown for the following reaction $A + B \to C$
$Expt. \ No.$ $[A]$ $[B]$ $Initial \ Rate$
$1$ $0.012$ $0.035$ $0.10$
$2$ $0.024$ $0.070$ $0.80$
$3$ $0.024$ $0.035$ $0.10$
$4$ $0.012$ $0.070$ $0.80$

For a gaseous reaction $2A + B \rightarrow C + D$,the rate of reaction is given by $Rate = K[A][B]$. If the volume of the container is reduced to $1/4$ of its original volume,what will be the ratio of the new rate to the original rate?

Determine the order of reaction on the basis of following data for the reaction $A + B \to C$.
Exp.$[A]$$[B]$Rate of reaction $(mol \ L^{-1} \ s^{-1})$
$1$$0.1$$0.1$$2 \times 10^{-3}$
$2$$0.4$$0.1$$0.8 \times 10^{-2}$
$3$$0.1$$0.2$$1.6 \times 10^{-2}$
(in $.5$)

The rate constant of a reaction is $1.388 \times 10^{-3} \ mol^{-2} \ L^{2} \ s^{-1}$. The order of the reaction is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo