A xrightarrow{Delta } B + C_{(gas)} xrightarr | vedclass

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(B) The reaction sequence represents the thermal decomposition of sodium bicarbonate $(NaHCO_3)$:$1$. $2NaHCO_3 \xrightarrow{\Delta} Na_2CO_3 + H_2O +

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$B$ is a metal carbonate which is insoluble in $H_2O$

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(B) The reaction sequence represents the thermal decomposition of sodium bicarbonate $(NaHCO_3)$:$1$. $2NaHCO_3 \xrightarrow{\Delta} Na_2CO_3 + H_2O + CO_2(g)$Here,$A = NaHCO_3$,$B = Na_2CO_3$,and $C = CO_2$.$2$. $CO_2$ reacts with lime water $(Ca(OH)_2)$ to form a milky precipitate:$Ca(OH)_2 + CO_2 \rightarrow CaCO_3(s) (D) + H_2O$$3$. Excess $CO_2$ reacts with $CaCO_3$ to form soluble calcium bicarbonate $(E)$:$CaCO_3 + H_2O + CO_2 \rightarrow Ca(HCO_3)_2 (E)$Evaluating the statements:- $A$ is $NaHCO_3$ (Correct).- $B$ is $Na_2CO_3$,which is soluble in $H_2O$ (Incorrect,as $Na_2CO_3$ is highly soluble).- $A$ $(NaHCO_3)$ is amphoteric,but $E$ $(Ca(HCO_3)_2)$ is also amphoteric (Correct).- $D$ is $CaCO_3$ (Correct).Thus,the incorrect statement is $B$.

$A$ $\xrightarrow{\Delta } B + C_{(gas)}$ $\xrightarrow{Ca(OH)_2} D_{(milky)} + H_2O$ $\xrightarrow{C_{(gas)}} E$
Then the incorrect statement is:

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$A$ $\xrightarrow{\Delta } B + C_{(gas)}$ $\xrightarrow{Ca(OH)_2} D_{(milky)} + H_2O$ $\xrightarrow{C_{(gas)}} E$Then the incorrect statement is: