(A) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the complex ion is $[Fe(H_2O)_5NO]^{2+}$.In this complex,$NO$ exists as $NO^+$. The oxidation state

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(A) In the brown ring complex $[Fe(H_2O)_5NO]SO_4$,the complex ion is $[Fe(H_2O)_5NO]^{2+}$.In this complex,$NO$ exists as $NO^+$. The oxidation state of $H_2O$ is $0$.Let the oxidation state of $Fe$ be $x$.$x + 5(0) + 1(+1) = +2$$x + 1 = +2$$x = +1$Therefore,the oxidation state of $Fe$ in the brown ring complex is $+1$.