The hexafluoroferrate (II) ion is an outer or | vedclass

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(C) The formula for the hexafluoroferrate $(II)$ ion is $[FeF_6]^{4-}$.In this complex,the oxidation state of $Fe$ is $+2$.The electronic configuratio

Vedclass · Accepted Answer

$4$

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(C) The formula for the hexafluoroferrate $(II)$ ion is $[FeF_6]^{4-}$.In this complex,the oxidation state of $Fe$ is $+2$.The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.Since $F^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals.Thus,the $3d$ orbitals contain $5$ electrons in the $t_{2g}$ and $e_g$ sets as follows: $t_{2g}^4 e_g^2$.The number of unpaired electrons is $4$.

List-$I$ (Complex/ion)	List-$II$ (Shape/geometry)
$A$. $[Pt(Cl)_2(NH_3)_2]$	$I$. Octahedral
$B$. $[Co(NH_3)_6]Cl_3$	$II$. Trigonal bipyramidal
$C$. $[NiCl_4]^{2-}$	$III$. Square planar
$D$. $[Fe(CO)_5]$	$IV$. Tetrahedral

The hexafluoroferrate $(II)$ ion is an outer orbital complex. The number of unpaired electrons in it is .............

Similar Questions

Match List-$I$ with List-$II$:
List-$I$ (Complex/ion) List-$II$ (Shape/geometry)
$A$. $[Pt(Cl)_2(NH_3)_2]$ $I$. Octahedral
$B$. $[Co(NH_3)_6]Cl_3$ $II$. Trigonal bipyramidal
$C$. $[NiCl_4]^{2-}$ $III$. Square planar
$D$. $[Fe(CO)_5]$ $IV$. Tetrahedral

Which of the following statements is correct regarding the complexes $[CoF_6]^{3-}$ and $[Co(NH_3)_6]^{3+}$?

How many unpaired electrons are present in the central metal ion of $[CoCl_4]^{2-}$?

The correct order of hybridization of the central atom in the following species $NH_3$,$[PtCl_4]^{2-}$,$PCl_5$,and $BCl_3$ is

The spin-only magnetic moment of $[MnBr_4]^{2-}$ is $5.9 \ BM$. Predict the geometry of the complex ion.

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