The complex [Co(NH_3)_5Br]SO_4 will give a wh | vedclass

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(A) The complex $[Co(NH_3)_5Br]SO_4$ dissociates in aqueous solution as $[Co(NH_3)_5Br]SO_4 \rightarrow [Co(NH_3)_5Br]^{2+} + SO_4^{2-}$.When $BaCl_2$

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$PbCl_2$

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(A) The complex $[Co(NH_3)_5Br]SO_4$ dissociates in aqueous solution as $[Co(NH_3)_5Br]SO_4 \rightarrow [Co(NH_3)_5Br]^{2+} + SO_4^{2-}$.When $BaCl_2$ or $Pb(NO_3)_2$ is added,the $SO_4^{2-}$ ions react to form a white precipitate of $BaSO_4$ or $PbSO_4$.Among the given options,$PbCl_2$ is not a suitable reagent for testing sulfate ions as it is sparingly soluble. However,if we consider the reaction of $SO_4^{2-}$ with $Pb^{2+}$ ions,$PbSO_4$ is a white precipitate.Since $PbCl_2$ is often used as a source of $Pb^{2+}$ ions in specific contexts,it is the most appropriate choice among the provided options to yield a white precipitate of $PbSO_4$.

The complex $[Co(NH_3)_5Br]SO_4$ will give a white precipitate with:

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