Which of the following complexes does not inv | vedclass

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(A) $1$. Inner orbital complexes involve the use of $(n-1)d$ orbitals for hybridization (e.g.,$d^2sp^3$).$2$. Outer orbital complexes involve the use

Vedclass · Accepted Answer

$[CoF_6]^{3-}$

Vedclass · Answer

(A) $1$. Inner orbital complexes involve the use of $(n-1)d$ orbitals for hybridization (e.g.,$d^2sp^3$).$2$. Outer orbital complexes involve the use of $nd$ orbitals for hybridization (e.g.,$sp^3d^2$).$3$. In $[CoF_6]^{3-}$,$F^-$ is a weak field ligand,so it does not cause pairing of electrons. The hybridization is $sp^3d^2$ (outer orbital).$4$. In $[Co(NH_3)_6]^{3+}$,$[Fe(CN)_6]^{3-}$,and $[Cr(NH_3)_6]^{3+}$,the ligands are strong enough or the electronic configuration allows for $d^2sp^3$ (inner orbital) hybridization.$5$. Therefore,$[CoF_6]^{3-}$ is the complex that does not involve inner orbital hybridization.

Coordination number and type of hybridisation	Distribution of hybrid orbitals in space
$(a)$. $4, sp^3$	$(i)$. trigonal bipyramidal
$(b)$. $3, sp^2$	$(ii)$. octahedral
$(c)$. $5, sp^3 d$	$(iii)$. tetrahedral
$(d)$. $6, sp^3 d^2$	$(iv)$. trigonal planar

Which of the following complexes does not involve inner orbital hybridization?

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