Which of the following configurations will show an outer orbital octahedral complex?

Hybridizations of the central atom in $[Fe(H_2O)_6]^{3+}$ and $[Co(NH_3)_6]^{3+}$,respectively,are

In $[Cu(NH_3)_4]SO_4$,$Cu$ has the following hybridization:

The correct order of $[FeF_6]^{3-}, [CoF_6]^{3-}, [Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$ complex species based on the number of unpaired electrons present is $:$

Using valence bond theory,explain the following in relation to the complexes given below: $[Mn(CN)_{6}]^{3-}, [Co(NH_{3})_{6}]^{3+}, [Cr(H_{2}O)_{6}]^{3+}, [FeCl_{6}]^{4-}$
$(i)$ Type of hybridisation.
$(ii)$ Inner or outer orbital complex.
$(iii)$ Magnetic behaviour.
$(iv)$ Spin only magnetic moment value.

Given below are two statements:
Statement $I$: $[Mn(CN)_6]^{3-}$,$[Fe(CN)_6]^{3-}$ and $[Co(C_2O_4)_3]^{3-}$ are $d^2sp^3$ hybridized.
Statement $II$: $[MnCl_6]^{3-}$ and $[FeF_6]^{3-}$ are paramagnetic and have $4$ and $5$ unpaired electrons,respectively.
In the light of the above statements,choose the correct answer from the options given below: