The product obtained by the reaction of CH_3M | vedclass

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Question

(C) Grignard reagents $(RMgX)$ act as strong bases when they react with compounds containing active hydrogen atoms (like alcohols,water,or amines).In

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$CH_4$

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(C) Grignard reagents $(RMgX)$ act as strong bases when they react with compounds containing active hydrogen atoms (like alcohols,water,or amines).In this reaction,$CH_3MgBr$ reacts with $C_2H_5OH$ to form methane $(CH_4)$ and magnesium ethoxy bromide $(Mg(OC_2H_5)Br)$.The reaction is: $CH_3MgBr + C_2H_5OH \rightarrow CH_4 + Mg(OC_2H_5)Br$.Therefore,the product is methane $(CH_4)$.

The product obtained by the reaction of $CH_3MgBr$ with $C_2H_5OH$ is .......

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