What will be X in the following reaction?{C_2 | vedclass

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(D) The reaction of ethyne $({C_2}{H_2})$ with water in the presence of $HgSO_4$ and $H_2SO_4$ is a hydration reaction.First,the addition of water to

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$CH_2 = CH - OH$

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(D) The reaction of ethyne $({C_2}{H_2})$ with water in the presence of $HgSO_4$ and $H_2SO_4$ is a hydration reaction.First,the addition of water to the triple bond occurs to form an unstable enol intermediate,which is $CH_2 = CH - OH$ (vinyl alcohol).This enol intermediate undergoes tautomerization to form the more stable carbonyl compound,acetaldehyde $(CH_3CHO)$.Therefore,$X$ is $CH_2 = CH - OH$.

What will be $X$ in the following reaction?
${C_2}{H_2} \xrightarrow[{HgSO_4 / H_2SO_4, 60^{\circ}C}]{{H_2O}} X \rightleftharpoons CH_3CHO$

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What will be $X$ in the following reaction?${C_2}{H_2} \xrightarrow[{HgSO_4 / H_2SO_4, 60^{\circ}C}]{{H_2O}} X \rightleftharpoons CH_3CHO$