Which of the following is not a functional is | vedclass

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(D) To determine the functional isomers,we first calculate the molecular formula for each compound:$A$: $C_3H_6O_3$ ($1$,$3$-dihydroxypropan$-2-$one)$

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$CH_2OH-CHOH-CH_2OH$

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(D) To determine the functional isomers,we first calculate the molecular formula for each compound:$A$: $C_3H_6O_3$ ($1$,$3$-dihydroxypropan$-2-$one)$B$: $C_3H_6O_3$ ($2$-hydroxypropanoic acid)$C$: $C_3H_6O_3$ ($2$,$3$-dihydroxypropanal)$D$: $C_3H_8O_3$ (propane$-1,2,3-$triol)Compounds $A$,$B$,and $C$ all have the same molecular formula $(C_3H_6O_3)$ but different functional groups (ketone,carboxylic acid,and aldehyde respectively),making them functional isomers.Compound $D$ has the molecular formula $C_3H_8O_3$,which is different from the others. Therefore,it is not a functional isomer of the others.

Which of the following is not a functional isomer of the others?

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