Which of the following compounds will exhibit | vedclass

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(B) For a compound to exhibit geometrical isomerism,each carbon atom of the double bond must be attached to two different groups.In $CH_3-CH=CH-CH_3$

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$CH_3-CH=CH-CH_3$

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(B) For a compound to exhibit geometrical isomerism,each carbon atom of the double bond must be attached to two different groups.In $CH_3-CH=CH-CH_3$ (but$-2-$ene),the first carbon of the double bond is attached to a $-H$ and a $-CH_3$ group,and the second carbon is also attached to a $-H$ and a $-CH_3$ group.Since both carbons have different groups attached,it exhibits geometrical isomerism (cis and trans forms).In the other options,at least one carbon of the double bond is attached to two identical groups (e.g.,two $-H$ atoms or two $-CH_3$ groups),so they do not show geometrical isomerism.

Which of the following compounds will exhibit geometrical isomerism?

Similar Questions

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