Which of the following exists in two geometri | vedclass

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(D) For a compound to exhibit geometrical isomerism,the carbon atoms involved in the double bond must be attached to two different groups.In option $D

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$CH_3CH_2-CH=CH-CH_3$

Vedclass · Answer

(D) For a compound to exhibit geometrical isomerism,the carbon atoms involved in the double bond must be attached to two different groups.In option $D$,$CH_3CH_2-CH=CH-CH_3$ (pent$-2-$ene),the carbon atoms of the double bond are attached to different groups ($H$ and $CH_3$ on one side,$H$ and $CH_2CH_3$ on the other).This allows for the existence of $cis$ and $trans$ isomers.Option $A$ is an alkyne,which does not show geometrical isomerism.Option $B$ has two identical $H$ atoms on the terminal carbon.Option $C$ has two identical $CH_3$ groups on one of the double-bonded carbons.

Which of the following exists in two geometrical isomeric forms?

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