Which of the following compounds will exhibit | vedclass

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(D) Metamerism arises due to the difference in the nature of alkyl groups attached to the same polyvalent functional group (e.g., $-O-$, $-CO-$, $-NH-

Vedclass · Accepted Answer

$C_2H_5-O-C_2H_5$

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(D) Metamerism arises due to the difference in the nature of alkyl groups attached to the same polyvalent functional group (e.g., $-O-$, $-CO-$, $-NH-$).$(A)$ $CH_3-O-C_2H_5$ (methoxyethane) is a metamer of $CH_3-CH_2-O-CH_3$ (same molecule) and can form metamers with $CH_3-CH_2-CH_2-O-CH_3$ ($1$-methoxypropane).$(B)$ $CH_3-O-CH_3$ (dimethyl ether) cannot exhibit metamerism as it has identical alkyl groups on both sides.$(C)$ $CH_3-CO-C_2H_5$ (butan$-2-$one) is a ketone. While it has a polyvalent group, it does not have a metamer with the same molecular formula because the carbonyl group position is fixed by the chain length.$(D)$ $C_2H_5-O-C_2H_5$ (diethyl ether) is a metamer of $CH_3-O-C_3H_7$ (methyl propyl ether). Both $(A)$ and $(D)$ are ethers that can exhibit metamerism. However, in standard chemistry problems of this type, $C_2H_5-O-C_2H_5$ is the classic example of an ether that forms metamers.Correct Answer: $(D)$

Column $I$ (Compounds)	Column $II$ (Relation)
$(i)$ $CH_3-CH_2-C(CH_3)_2-Cl$ and $(CH_3)_3C-Cl$	$(P)$ Homologues
$(ii)$ $C_6H_5-O-CH_2-CH_3$ and $C_6H_5-O(CH_3)-CH_3$ (ortho-methylanisole)	$(Q)$ Functional group isomers
$(iii)$ $C_6H_5-O-CH_3$ and $2-methylphenol$	$(R)$ Metamers
$(iv)$ $CH_3-CH(CH_3)-CH_2-OH$ and $(CH_3)_3C-OH$	$(S)$ Position isomers

Which of the following compounds will exhibit metamerism?

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