The number of stereoisomers for pent-3-en-2-o | vedclass

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Question

(C) The structure of $pent-3-en-2-ol$ is $CH_3-CH(OH)-CH=CH-CH_3$.It contains one chiral carbon atom at $C-2$ and one carbon-carbon double bond at $C-

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) The structure of $pent-3-en-2-ol$ is $CH_3-CH(OH)-CH=CH-CH_3$.It contains one chiral carbon atom at $C-2$ and one carbon-carbon double bond at $C-3$ which can show geometrical isomerism.The chiral center at $C-2$ can exist in two configurations: $(R)$ and $(S)$.The double bond at $C-3$ can exist in two configurations: $(cis)$ and $(trans)$.Since there are two stereogenic centers (one chiral center and one double bond),the total number of stereoisomers is $2^n$,where $n=2$.Total stereoisomers = $2^2 = 4$.

The number of stereoisomers for $pent-3-en-2-ol$ is ...........

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