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(B) The reaction involves the electrophilic addition of $HBr$ to the vinyl ether $CH_2=CH-OCH_3$. $1$. The proton $(H^+)$ from $HBr$ attacks the termi

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$CH_3-CHBr-OCH_3$

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(B) The reaction involves the electrophilic addition of $HBr$ to the vinyl ether $CH_2=CH-OCH_3$. $1$. The proton $(H^+)$ from $HBr$ attacks the terminal carbon $(CH_2)$ to form a stable carbocation,$CH_3-CH^+-OCH_3$,which is stabilized by the resonance effect of the oxygen atom (lone pair donation). $2$. The bromide ion $(Br^-)$ then attacks the carbocation to form the product $CH_3-CHBr-OCH_3$. $3$. Under anhydrous conditions,the ether linkage remains intact,and the product is $1-bromo-1-methoxyethane$ $(CH_3-CHBr-OCH_3)$.

What is the product formed by the reaction of $HBr$ with $CH_2=CH-OCH_3$ under anhydrous conditions at room temperature?

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