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(C) Step $1$: The reaction of $CH_3CH_2C \equiv CH$ (but$-1-$yne) with $HCl$ follows Markovnikov's rule. The $H^+$ adds to the terminal carbon,and $Cl

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$CH_3CH_2CCl(I)CH_3$

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(C) Step $1$: The reaction of $CH_3CH_2C \equiv CH$ (but$-1-$yne) with $HCl$ follows Markovnikov's rule. The $H^+$ adds to the terminal carbon,and $Cl^-$ adds to the internal carbon,forming $B$ ($CH_3CH_2CCl=CH_2$,$2$-chlorobut$-1-$ene).Step $2$: The reaction of $CH_3CH_2CCl=CH_2$ with $HI$ also follows Markovnikov's rule. The $H^+$ adds to the terminal carbon $(CH_2)$,and $I^-$ adds to the carbon already bonded to $Cl$ (the more substituted carbon),resulting in the geminal dihalide $C$ ($CH_3CH_2CCl(I)CH_3$,$2$-chloro$-2-$iodobutane).

Identify the product $C$ in the following reaction sequence:
$CH_3CH_2C \equiv CH + HCl \to B \xrightarrow{HI} C$

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Identify the product $C$ in the following reaction sequence:$CH_3CH_2C \equiv CH + HCl \to B \xrightarrow{HI} C$